Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 16 - Section 16.4 - Exercises and Problems - Page 309: 14

Answer

Please see the work below.

Work Step by Step

We know that $\Delta T_F=(\frac{9}{5})\Delta T_C$ We plug in the known values to obtain: $\Delta T_F=(\frac{9}{5})(10)$ $\Delta T_F=18F^{\circ}$
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