Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 272: 51

Answer

77.89 m/s

Work Step by Step

Here we use the equation $V=\sqrt {\frac{F}{\mu}}$ where, V - speed of the wave, F - tension force, $\mu$ - mass per unit length The maximum speed occurs when the F becomes maximum. $V_{max}=\sqrt {\frac{F_{max}}{\mu}}$ ; Let's plug known values into this equation. $V_{max}=\sqrt {\frac{415kgm/s^{2}}{68.4\times10^{-3}kg/m}}=77.89 m/s$
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