Answer
$v=0.0075\cdot 10^{9}\text{ms}^{-1}$
Work Step by Step
$$v=\dfrac{h}{m\lambda}=\dfrac{6.63\cdot 10^{-34}\text{Js}}{9.1\cdot 10^{-31}\text{kg}\cdot96\cdot 10^{-12}\text{m}}=0.0075\cdot 10^{9}\text{ms}^{-1}$$
General Chemistry (4th Edition)
by McQuarrie, Donald A.
Published by
University Science Books
ISBN 10:
1891389602
ISBN 13:
978-1-89138-960-3
Chapter 4 Early Quantum Theory - Problems - Page 133: 34
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