Answer
2.067 J
Work Step by Step
We find:
$E_{k}=h\nu-h\nu_{0}=h\frac{c}{\lambda}-h\nu_{0}$
$=6.626\times10^{-34}\,J\cdot s\times(\frac{3.00\times10^{8}\,m/s}{400.0\times10^{-9}\,m}-4.38\times10^{14}\,s^{-1})$
$=2.067\,J$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.