Answer
3.92 g
Work Step by Step
We find:
Grams of $O_{2}$=
$10.0\,g\times\frac{1\,mol\,KClO_{3}}{122.55\,g}\times\frac{3\,mol\,O_{2}}{2\,mol\,KClO_{3}}\times\frac{32.0\,g}{1\,mol\,O_{2}}$
$=3.92\,g$
General Chemistry (4th Edition)
by McQuarrie, Donald A.
Published by
University Science Books
ISBN 10:
1891389602
ISBN 13:
978-1-89138-960-3
Chapter 11 Chemical Calculations - Problems - Page 386: 34
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