General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 11 Chemical Calculations - Problems - Page 386: 32

Answer

59.1 g

Work Step by Step

Grams of sodium iodide to be used= $50.0\,g\times\frac{1\,mol\,I_{2}}{253.8\,g}\times\frac{2\,mol\,NaI}{1\,mol\,I_{2}}\times\frac{149.89\,g}{1\,mol\,NaI}$ $=59.1\,g$
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