Answer
36.3 g
Work Step by Step
Grams of oxygen required=
$10.0\,g\,\times\frac{1\,mol\, C_{3}H_{8}}{44.1\,g}\times\frac{5\,mol\,O_{2}}{1\,mol\,C_{3}H_{8}}\times\frac{32.0\,g}{1\,mol\,O_{2}}$
$=36.3\,g$
General Chemistry (4th Edition)
by McQuarrie, Donald A.
Published by
University Science Books
ISBN 10:
1891389602
ISBN 13:
978-1-89138-960-3
Chapter 11 Chemical Calculations - Problems - Page 386: 31
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