Answer
The amount of reaction that occurs is equal to 0.115 mol.
Work Step by Step
1. Divide the amount (in mols) by the coefficient of $N_2O_3$:
$\frac{0.115 mol (N_2O_3)}{ 1 (N_2O_3/reaction)} = 0.115 mol - reaction$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 4 - Energy and Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 189c: 51b
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