Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 4 - Energy and Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 189c: 50c

Answer

Heat transfer = $66.9kJ$

Work Step by Step

1. Divide the amount (in moles) by the coefficient of $C$: $\frac{0.432}{ 3} = 0.144 mol - reaction$ 2. Find the necessary heat: $0.144mol-reaction \times 464.8 kJ/mol-reaction = 66.9kJ$
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