Answer
The theoretical mass is equal to $85.2g (CH_3OH)$.
Work Step by Step
1. Calculate the number of moles of $CO$:
12.01* 1 + 16* 1 = 28.01g/mol
$74.5g \times \frac{1 mol}{ 28.01g} = 2.66mol (CO)$
- The balanced reaction is:
$CO + 2H_2 -- \gt CH_3OH$
The ratio of $CO$ to $CH_3OH$ is 1 to 1:
$2.66 mol (CO) \times \frac{ 1 mol(CH_3OH)}{ 1 mol (CO)} = 2.66mol (CH_3OH)$
2. Calculate the mass of $CH_3OH$:
12.01* 1 + 1.01* 3 + 16* 1 + 1.01* 1 = 32.05g/mol
$2.66 mol \times \frac{ 32.05 g}{ 1 mol} = 85.2g (CH_3OH)$
