Answer
526g of carbon monoxide.
Work Step by Step
1. Calculate the number of moles of $Fe_2O_3$:
55.85* 2 + 16* 3 = 159.7g/mol
$1000g \times \frac{1 mol}{ 159.7g} = 6.262mol (Fe_2O_3)$
The ratio of $Fe_2O_3$ to $CO$ is 1 to 3:
$6.262 mol (Fe_2O_3) \times \frac{ 3 mol(CO)}{ 1 mol (Fe_2O_3)} = 18.79mol (CO)$
2. Calculate the mass of $CO$:
12.01* 1 + 16* 1 = 28.01g/mol
$18.79 mol \times \frac{ 28.01 g}{ 1 mol} = 526g (CO)$
