Answer
$CCl_2F_2 + 2Na_2C_2O_4 -- \gt C + 4CO_2 + 2NaCl + 2NaF$
Work Step by Step
1. Write the unbalanced reaction, based on the reactants and products described in the exercise:
$CCl_2F_2 + Na_2C_2O_4 -- \gt C + CO_2 + NaCl + NaF$
2. Let's start by giving the coefficients of the chlorine and fluorine compounds:
$1CCl_2F_2 + Na_2C_2O_4 -- \gt C + CO_2 + 2NaCl + 2NaF$
3. Now, we have a total of 4 sodiums on the products side, so we have to put a 2 on the sodium oxalate:
$1CCl_2F_2 + 2Na_2C_2O_4 -- \gt C + CO_2 + 2NaCl + 2NaF$
4. We have 8 oxygens on the reactant's side, so we have to put a 4 on the carbon dioxide.
$1CCl_2F_2 + 2Na_2C_2O_4 -- \gt C + 4CO_2 + 2NaCl + 2NaF$
Now, the reaction is totally balanced.
