Chapter 3 - Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 148f: 89

21.0 g

1. Find the number of moles: $Concentration(M) = \frac{n(mol)}{V(L)}$ $0.200 = \frac{n(mol)}{0.5}$ $0.200 * 0.500 = n(mol)$ $0.100 moles = n(mol)$ 2. Determine the molar mass of this compound ($CuSO_4+ 5(H_2O)$: 12.01* 1 + 12.01* 1 + 32.07* 1 + 16* 4 + 5 * ( 1.008* 2 + 16.0* 1 ) = 210.2g/mol 3. Calculate the mass $mm(g/mol) = \frac{mass(g)}{n(mol)}$ $mm(g/mol) * n(mol) = mass(g)$ $ 210.2 * 0.100 = mass(g)$ $21.0 = mass(g)$