Answer
The volume of this solution is equal to 0.989 L, or 989 ml.
Work Step by Step
1. Determine the molar mass of this compound ($KMnO_4$):
39.1* 1 + 54.94* 1 + 16* 4 = 158.04g/mol
2. Calculate the number of moles:
$mm(g/mol) = \frac{mass(g)}{n(mol)}$
$ 158.04 = \frac{322}{n(mol)}$
$n(mol) = \frac{322}{ 158.04}$
$n(mol) = 2.037$
3. Find the volume:
$Concentration(M) = \frac{n(mol)}{V(L)}$
$2.06 = \frac{2.037}{V(L)}$
$V(L) = \frac{2.037}{2.06}$
$V(L) = 0.989\ L $
