Answer
The molarity of potassium dicromate is equal to $0.0159M$
Work Step by Step
1. Calculate the molar mass $(K_2Cr_2O_7)$:
39.1* 2 + 52* 2 + 16* 7 = 294.2g/mol
2. Calculate the number of moles $(K_2Cr_2O_7)$
$n(moles) = \frac{mass(g)}{mm(g/mol)}$
$n(moles) = \frac{ 2.335}{ 294.2}$
$n(moles) = 7.937\times 10^{- 3}$
3. Find the concentration in mol/L $(K_2Cr_2O_7)$:
1000 ml = 1L
500 ml = 0.500L
$C(mol/L) = \frac{n(moles)}{volume(L)}$
$ C(mol/L) = \frac{ 7.937\times 10^{- 3}}{ 0.500} $
$C(mol/L) = 0.0159M$
