Answer
$10.0\,JK^{-1}mol^{-1}$
Work Step by Step
$\Delta_{r}S^{\circ}=\frac{q_{rev}}{T}=\frac{5.00\times10^{3}\,J/mol}{500.\,K}=10.0\,JK^{-1}mol^{-1}$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 18 - Thermodynamics: Directionality of Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 737b: 34a
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
