Answer
$2.63\,JK^{-1}mol^{-1}$
Work Step by Step
$\Delta_{r}S^{\circ}=\frac{q_{rev}}{T}=\frac{0.775\times10^{3}\,J/mol}{295\,K}=2.63\,JK^{-1}mol^{-1}$
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