Answer
$112\,JK^{-1}mol^{-1}$
Work Step by Step
$\Delta _{r}S^{\circ}=\frac{\Delta H_{vap}}{T_{b}}=\frac{39.3\times10^{3}\,J/mol}{(78.3+273.15)K}=112\,JK^{-1}mol^{-1}$
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