Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 16 - Thermodynamics: Directionality of Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 737e: 75a

Answer

Can be harnessed to do useful work.

Work Step by Step

$\Delta_{r}G^{\circ}=\Sigma n_{p}\Delta_{f}G^{\circ}(products)-\Sigma n_{r}\Delta _{f}G^{\circ}(reactants)$ $=[12\Delta_{f}G^{\circ}(CO_{2},g)+6\Delta_{f}G^{\circ}(H_{2}O,g)]-[2\Delta_{f}G^{\circ}(C_{6}H_{6},l)+15\Delta_{f}G^{\circ}(O_{2},g)]$ $=[12(-394.359\,kJ/mol)+6(-228.572\,kJ/mol)]-[2(124.5\,kJ/mol)+15(0)]$ $=-6352.7\,kJ/mol$ As $\Delta _{r}G^{\circ}$ is negative, the reaction is capable of being harnessed to do useful work. Up to 6352.7 kJ/mol of useful work can be done.
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