Answer
$-3.0\times10^{2}\,kJ/mol$
Work Step by Step
$\Delta _{r}G^{\circ}=-RT\ln K=-RT\ln K_{p}$
$=-(8.314\,Jmol^{-1}K^{-1})(298\,K)(\ln 4.2\times10^{52})$
$=-3.0\times10^{5}\,J/mol=-3.0\times10^{2}\,kJ/mol$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 16 - Thermodynamics: Directionality of Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 737e: 74a
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