Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 16 - Thermodynamics: Directionality of Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 737d: 55

Answer

$\Delta_{r}G^{\circ}=28.63\,kJ/mol$ The reaction is reactant-favored.

Work Step by Step

$\Delta_{r}G^{\circ}=\Delta _{r}H^{\circ}-T\Delta _{r}S^{\circ}$ $=41.17\,kJ/mol-(25+273)K(42.08\,JK^{-1}mol^{-1})$ $=41.17\,kJ/mol-(298\,K)(0.04208\,kJK^{-1}mol^{-1})$ $=28.63\,kJ/mol$ $\Delta_{r}G^{\circ}$ is positive. $\implies$ The reaction is reactant-favored.
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