Answer
Reactants:
Acid: $H_2O$
Base: $HC{O_2}^-$
Products:
Conjugate base: $OH^-$
Conjugate acid: $HCOOH$
Work Step by Step
Reactants: Left side of the reaction.
Products: Right side.
1. Identify the acid and the base of the reactants:
- $H_2O$ is turning into $OH^-$; therefore, it is donating one proton, so it is the acid.
- $HC{O_2}^-$ is turning into $HCOOH$; therefore, it is receiving one proton, so it is the base.
2. Identify the conjugate acid and base:
- The conjugate base is the result of an acid losing a $H^+$. Since $H_2O$ is the acid, $OH^-$ is the conjugate base.
- The conjugate acid is the result of a base gaining a $H^+$. Since $HC{O_2}^-$ is the base, $HCOOH$ is the conjugate acid.
