Answer
Reactants:
Acid: $N{H_4}^+$
Base: $S^{2-}$
Products:
Conjugate base: $NH_3$
Conjugate acid: $HS^-$
Work Step by Step
Reactants: Left side of the reaction.
Products: Right side.
1. Identify the acid and the base of the reactants:
- $N{H_4}^+$ is turning into $NH_3$; therefore, it is donating one proton, so it is the acid.
- $S^{2-}$ is turning into $HS^-$; therefore, it is receiving one proton, so it is the base.
2. Identify the conjugate acid and base:
- The conjugate base is the result of an acid losing a $H^+$. Since $N{H_4}^+$ is the acid, $NH_3$ is the conjugate base.
- The conjugate acid is the result of a base gaining a $H^+$. Since $S^{2-}$ is the base, $HS^-$ is the conjugate acid.
