Answer
Reactants:
- Acid: $H_2O$
- Base: $HS^-$
Products:
- Conjugate base: $OH^-$
- Conjugate acid: $H_2S$
Work Step by Step
Reactants: Left side of the reaction.
Products: Right side.
1. Identify the acid and the base of the reactants:
- $H_2O$ is turning into $OH^-$; therefore, it is donating one proton, so it is the acid.
- $HS^-$ is turning into $H_2S$; therefore, it is receiving one proton, so it is the base.
2. Identify the conjugate acid and base:
- The conjugate base is the result of an acid losing a $H^+$. Since $H_2O$ is the acid, $OH^-$ is the conjugate base.
- The conjugate acid is the result of a base gaining a $H^+$. Since $HS^-$ is the base, $H_2S$ is the conjugate acid.
