Answer
Mass fraction= 0.0836
Weight percent= $ 8.36\%$
Work Step by Step
Mass fraction of ethanol=
$\frac{mass\,of\,ethanol}{mass\,of\, ethanol+mass\,of\, benzene}= \frac{4.56\,g}{4.56\,g+50.0\,g}$
$=0.0836$
Weight percent= mass fraction$\times100\%$
$=0.0836\times100\%=8.36\%$