Answer
0.764 M
Work Step by Step
Mass fraction of sucrose$=\frac{23.2}{100}=0.232$
Let the volume of the solution be 1 L=1000 mL.
Then, mass of the solution=$density\times volume$
$= 1.127\,g/mL \times1000\,mL=1127\,g$
Mass of sucrose= mass fraction$\times$ mass of the solution
$=0.232\times1127\,g=261.464\,g$
Molar mass of sucrose ($C_{12}H_{22}O_{11}$)
=342.3 g/mol
Moles of sucrose= $\frac{mass\,of\, sucrose}{molar\,mass}=\frac{261.464\,g}{342.3\,g/mol}$
$=0.764\,mol$
Molarity of sucrose= $\frac{moles\,of\, sucrose}{volume\, of\, solution\,in\,L}=\frac{0.764\,mol}{1\,L}=0.764\,M$
