Answer
83.9 g KCl
Work Step by Step
Molarity M= 0.750 M
Volume of solution in litre= 1.50 L
Number of moles of KCl n=MV=$0.750M\times1.50L= 1.125 mol$
Mass in grams of KCl= n$\times$ Molar mass of $KCl$
$= 1.125 mol\times74.55 g/mol=83.9 g$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 13 - The Chemistry of Solutes and Solutions - Questions for Review and Thought - Topical Questions - Page 605c: 44b
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