Answer
Molality= $15\,m$
Mole fraction= $0.22$
Work Step by Step
Mass percent of HCl= $36\%$
$\implies $ 100 g solution contains 36 g HCl.
Mass of water= $100\,g-36\,g=64\,g$
Molality= $\frac{\text{moles of solute}}{\text{mass of solvent in kg}}$
$=\frac{\frac{36\,g}{36.46\,g/mol}}{64\times10^{-3}\,kg}=15\,m$
Mole fraction of HCl, $X_{HCl}=\frac{n_{HCl}}{n_{HCl}+n_{H_{2}O}}$
$=\frac{\frac{36\,g}{36.46\,g/mol}}{\frac{36\,g}{36.46\,g/mol}+\frac{64\,g}{18.0\,g/mol}}$
$=\frac{0.98738\,mol}{0.98738\,mol+3.5555\,mol}$
$=0.22$
