Answer
0.340 L
Work Step by Step
Molarity after dilution $M_{2}=\frac{\frac{3.05\,g}{166.0\,g/mol}}{25.0\times10^{-3}\,L}=0.73494\,M$
We use the relation $M_{1}V_{1}=M_{2}V_{2}$ to obtain the final volume.
$V_{2}=\frac{M_{1}V_{1}}{M_{2}}=\frac{(5.00\,M)(50.0\,mL)}{0.73494\,M}$
$=340\,mL=0.340\,L$
