Answer
1.44 L
Work Step by Step
Molarity after dilution $M_{2}=\frac{\frac{4.67\,g}{134.45\,g/mol}}{50.0\times10^{-3}\,L}=0.694682\,M$
We use the relation $M_{1}V_{1}=M_{2}V_{2}$ to obtain the final volume.
$V_{2}=\frac{M_{1}V_{1}}{M_{2}}=\frac{(8.00\,M)(125\,mL)}{0.694682\,M}$
$=1440\,mL=1.44\,L$
