Answer
Sn
Work Step by Step
Number of moles of $O$:
$(0.452-0.356)\ g\div 15.9994\ g/mol= 6.00\ mmol$, $3.00\ mmol$ of M
Atomic weight of M:
$0.356\ g\div 0.003\ mol= 118.7\ g/mol$, closest to Sn
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179h: 95
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