Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179h: 102

Answer

$0.77\ g$

Work Step by Step

Volume: $3.00\ m^2\times 250\times 0.60\times10^{-9}\ m=4.5\times10^{-7}\ m^3=0.45\ cm^3$ Mass: $0.45\ cm^3\times 1.0\ g/cm^3=0.45\ g$ Number of moles of the monomer equals the number of moles of $(CH_2)_2SiCl_2$: $0.45\ g\div 74.15\ g/mol=6.07\ mmol$ Mass of $(CH_2)_2SiCl_2$: $6.07\ mmol\times 127.04\ g/mol=0.771\ g$
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