Answer
$C_{10}H_{20}O$
Work Step by Step
Number of moles of $CO_2$:
$269\ mg\div 44.01\ mg/mmol=6.11\ mmol$, $6.11\ mmol$ of C, $73.4\ mg$
Number of moles of water:
$111\ mg\div 18.015\ mg/mmol=6.16\ mmol$, $12.32\ mmol$ of H, $12.4\ mg$
Number of moles of oxygen:
$(95.6-73.4-12.4)\ mg\div 15.9994\ mg/mmol=0.61\ mmol$
O/C Ratio: $0.10=1/10$
H/C Ratio: $2.03\approx 2$
$C_{10}H_{20}O$
