Answer
D
Work Step by Step
Barium is from group 2, hence : $Ba^{2+}$ is its cation, so the anion molybdate is $MoO_4^{2-}$
Sodium molybdate is then $Na_2MoO_4$.
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95i: 141
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