Chemistry and Chemical Reactivity (9th Edition)

by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.

Published by Cengage Learning

ISBN 10: 1133949649

ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95i: 135

Answer

$1240\ kg\ Cr_2O_3$

Work Step by Step

Atomic weights (g/mol): $Cr: 51.996,\ O: 15.999$ Molar mass: $151.99\ g/mol$ Mass fraction of Cr: $2\times51.996/151.99\times100\%=68.42\%$ For 850 kg of Cr: $850\ kg\ Cr\div(68.42 \ kg\ Cr/100\ kg\ Cr_2O_3)=1240\ kg\ Cr_2O_3$

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