Answer
$7.36\ kg$ of iron
Work Step by Step
Atomic weights (g/mol):
$Fe: 55.845, \ S: 32.06$
Molar mass of $FeS_2$: $119.965\ g/mol$
Mass fraction of Fe: $55.845\div119.965\times100\%=46.55\%$
In 15.8 kg of iron pyrite:
$15.8\times46.55/100=7.36\ kg$