Answer
$0.011\ g/L$
Work Step by Step
$CaOx(s)\leftrightarrow Ca^{2+}(aq)+Ox^{2-}(aq)$
$Ksp=[Ca^{2+}][Ox^{2-}]=s^2$
$s=\sqrt{4\times10^{-9}}$
$s=6.32\times10^{-5}\ M$
$S=6.32\times10^{-5}\ M\times 168.18\ g/mol=0.011\ g/L$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677e: 94
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