Answer
$K=3.75\times10^{-6}$
Left
Work Step by Step
$K=[OH^-]^2/[CN^-]^2=Ksp(Zn(OH)_2)/Ksp(Zn(CN)_2)$
$K=3\times10^{-17}/(8\times10^{-12})$
$K=3.75\times10^{-6}$
Since $K < 1$, the equilibrium lie predominantly to the left.
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677e: 92
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