Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - Study Questions - Page 629f: 94

Answer

$pH=3.39$

Work Step by Step

$K=[P][H_3O^+]/[PH^+]=K_w/K_{b,P}$ $6.67\cdot10^{-6}=x\cdot x/(0.025-x)$ $x=[H_3O^+]=0.000405\ M$ $pH=3.39$
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