Answer
$pH=3.39$
Work Step by Step
$K=[P][H_3O^+]/[PH^+]=K_w/K_{b,P}$
$6.67\cdot10^{-6}=x\cdot x/(0.025-x)$
$x=[H_3O^+]=0.000405\ M$
$pH=3.39$
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