Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - Study Questions - Page 629f: 91

Answer

$pKa=4.86$

Work Step by Step

$[H_3O^+]=10^{-3.44}=3.63\cdot10^{-4}\ M=[A^-]$ $K_a=[H_3O^+][A^-]/[HA]$ $K_a=(3.63\cdot10^{-4})^2/0.0096$ $K_a=1.37\cdot10^{-5}$ $pKa=4.86$
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