Answer
See the answer below.
Work Step by Step
$K_{b,NH_3}=1.8\cdot10^{-5}$
$H_3O^++NH_3\leftrightarrow NH_4^++H_2O$
$K\approx[NH_4^+]/[H_3O^+][NH_3]=K_{b,NH_3}/K_w$
$K=1.8\cdot10^9$
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