Answer
See the answer below.
Work Step by Step
The number of moles of solvent:
$955g\div18.015\ g/mol=53.01\ mol$
The number of moles of solute:
$0.125=(n)\div(n+53.01)$
$0.125n+6.626=n$
$n=7.57\ mol$
Mass of ethylene glycol:
$7.57\ mol\times62.07\ g/mol=470.06\ g$
The molality of ethylene glycol:
$7.57\ mol\div (955/1000)kg=7.9\ m$
