Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505: 6

Answer

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Work Step by Step

The number of moles of Na2NO3: $0.0512\ m=n/(500/1000\ kg)\rightarrow n=0.026\ mol$ The mass of Na2CO3 required: $0.026\ mol\times 107.98\ g/mol=2.76\ g$ The number of moles of water: $500\ g\div18.015\ g/mol=27.75\ mol$ Mole fraction of Na2CO3: $0.026\div(0.026+27.75)=0.00094$
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