Answer
See the answer below.
Work Step by Step
The number of moles of solvent:
$425 g\div18.015\ g/mol=23.59\ mol$
The number of moles of solute:
$0.093=(n)\div(n+23.59)$
$0.093n+2.194=n$
$n=2.42\ mol$
Mass of glycerol:
$2.42\ mol\times92.09\ g/mol=222.76\ g$
The molality of glycerol:
$2.42\ mol\div (425/1000)kg=5.69\ m$