Answer
Mass defect = 0.98252 amu
Nuclear binding energy = 8.553 MeV/nucleon
Work Step by Step
Mass defect=[Z(mass $^{1}_{1}H$)+(A-Z)(mass $^{1}_{0}n$)]-mass $^{107}_{47}Ag$
=47(1.00783 amu)+60(1.00866 amu)- 106.905092 amu
=0.98252 amu.
Nuclear binding energy=$0.98252\,amu\times\frac{931.5\,MeV}{1\,amu}=915.2\,MeV$
Nuclear binding energy per nucleon=
$\frac{Binding\,energy}{A}=\frac{915.2\,MeV}{107\,nucleons}=8.553\,MeV/nucleon$
