Answer
$9.0\times10^{13}\,J$
Work Step by Step
Mass $m=1.0\,g=1.0\times10^{-3}\,kg$
Speed of the light $c=3.0\times10^{8}\,m/s$
Energy $E=mc^{2}=1.0\times10^{-3}\,kg\times(3.0\times10^{8}\,m/s)^{2}$
$=9.0\times10^{13}\,J$
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 19 - Sections 19.1-19.12 - Exercises - Problems by Topic - Page 947: 65
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
