Answer
Mass defect = 0.54369 amu
Nuclear binding energy = 8.732 MeV/nucleon
Work Step by Step
Mass defect=[Z(mass $^{1}_{1}H$)+(A-Z)(mass $^{1}_{0}n$)]-mass $^{58}_{28}Ni$
=28(1.00783 amu)+30(1.00866 amu)- 57.935346 amu
=0.54369 amu.
Nuclear binding energy=$0.54369\,amu\times\frac{931.5\,MeV}{1\,amu}=506.45\,MeV$
Nuclear binding energy per nucleon=
$\frac{Binding\,energy}{Mass\,number}=\frac{506.45\,MeV}{58\,nucleons}=8.732\,MeV/nucleon$
