Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 19 - Sections 19.1-19.12 - Exercises - Problems by Topic - Page 946: 42c

Answer

Alpha decay

Work Step by Step

Atomic Number = 87, Protons = 87 Fro Fr-202, Atomic Mas = 202, Neutrons = 202-87 = 115 N/Z = 115/87 = 1.32 The value is below the valley of stability, hence mode of decay will be alpha decay
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