Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 19 - Sections 19.1-19.12 - Exercises - Problems by Topic - Page 946: 42b

Answer

Beta emission

Work Step by Step

Atomic Number = 52, Protons = 52 Fro Te-139, Atomic Mas = 139, Neutrons = 139-52 = 87 N/Z = 87/52 = 1.67 The value is above the valley of stability, Hence most likely mode of decay will be beta emission
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