Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 19 - Sections 19.1-19.12 - Exercises - Problems by Topic - Page 945: 36c

Answer

$^{237}_{93}Np$

Work Step by Step

Np-237 undergoes alpha decay to form U-233 $^{237}_{93}Np → ^{233}_{92}U + ^{4}_{2}He $
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